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[cc lang=”c”]
#include
main()
{
void print_head(int x,int y); /*打印头文件*/
void print_month(int x,int y); /*打印月历*/
int days_of_month(int x,int y); /*计算指定年月的天数*/
int leap(int x,int y); /*计算指定年月1号是星期几*/
int i,days,year,month,firstday;
char choose;
do
{printf (“\n\nplease input the year(0000~9999):\n\n”);
scanf (“%d”,&year);
if (year<0||year>9999) printf (“WANNING:ERROR,please input again!”);}
while (year<0||year>9999);
printf (“\n\n”);
do
{printf (“please input the month(0~12)\n\n\n”);
scanf (“%d”,&month);
if (month<=0||month>12) printf (“WANNING:ERROR,please input again!”);}
while (month<=0||month>12);
printf (“\n\n”);
days=days_of_month(year,month); /*调用函数*/
firstday=leap(year,month);
print_head(year,month);
print_month(firstday,days);
choose=getchar();
printf (“\n\n\n”);
printf(“would you like to continue(y/n):\n\n”);
scanf(“%c”,&choose);
if (choose==’y’||choose==’Y’) main();
}

days_of_month(int x,int y)
{
int z;
switch (y)
{case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12: z=31;break;
case 4:
case 6:
case 9:
case 11: z=30;break;
case 2:
{if ((x%4==0&&x%100!=0)||(x%400==0)) z=29;
else z=28;break;
}
}
return z;
}

leap(int x,int y)
{
int z,i,moday;
z=(x+(x-1)/4-(x-1)/100+(x-1)/400)%7;
for (i=1;i

未经允许不得转载：Bcoder资源网 » c语言简单的万年历实现

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